Evaluator
William E. Acree, Jr. Department of Chemistry University of North TexasEvaluation
Regressional analysis of the experimental data as Ln x1 versus 1/T yielded the following mathematical relationship: Ln x1 = - 2626.1 (1/T) + 7.4567 (r=0.9999) for variation of naphthalene solubility with absolute temperature (see graph below).
Figure
Sources:
4
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