Evaluator
William E. Acree, Jr. Department of Chemistry University of North TexasEvaluation
Regressional analysis of the experimental data as Ln x1 versus 1/T yielded the following mathematical relationship: Ln x1 = - 3849.6 (1/T) + 10.789 (r=0.9964) for variation of naphthalene solubility with absolute temperature (see graph below).
Sources:
5
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